4(x^-3)/x=x+2

Solution for 4(x^-3)/x=x+2 equation:

4(x^-3)/x=x+2

We move all terms to the left:

4(x^-3)/x-(x+2)=0


Domain of the equation: x!=0

x∈R


We get rid of parentheses

4(x^-3)/x-x-2=0

We multiply all the terms by the denominator


4(x^-3)-x*x-2*x=0

We add all the numbers together, and all the variables

-2x+4(x^-3)-x*x=0

We multiply parentheses

-2x+4x-x*x-12=0

Wy multiply elements

-1x^2-2x+4x-12=0

We add all the numbers together, and all the variables

-1x^2+2x-12=0

a = -1; b = 2; c = -12;
Δ = b2-4ac
Δ = 22-4·(-1)·(-12)
Δ = -44
Delta is less than zero, so there is no solution for the equation